Comments on: PHP Recursive Strings http://www.bretkuhns.com/blog/2009/11/php-recursive-strings/ Programming, Cars, and Life Fri, 03 Feb 2012 15:37:50 +0000 http://wordpress.org/?v=2.9.2 hourly 1 By: Bret Kuhns http://www.bretkuhns.com/blog/2009/11/php-recursive-strings/comment-page-1/#comment-8 Bret Kuhns Thu, 14 Jan 2010 19:39:42 +0000 http://www.bretkuhns.com/blog/?p=1#comment-8 Hey Noah! I came to the same conclusion and you're exactly right. That's how I solved the problem. I guess I should've mentioned that here, huh? I must have gotten too used to compiled languages for a while and PHP's line-by-line interpreting threw me a curve ball here. Hey Noah! I came to the same conclusion and you’re exactly right. That’s how I solved the problem. I guess I should’ve mentioned that here, huh? I must have gotten too used to compiled languages for a while and PHP’s line-by-line interpreting threw me a curve ball here.

]]> By: Noah http://www.bretkuhns.com/blog/2009/11/php-recursive-strings/comment-page-1/#comment-7 Noah Thu, 14 Jan 2010 19:32:38 +0000 http://www.bretkuhns.com/blog/?p=1#comment-7 This is what I would guess is happening: 1. PHP creates $a. 2. The initializer creates $a[0]. When it does this, $a[1] has no value since it has not yet been assigned, so "test {$a[1]}" evalulates to just "test ". 3. Same with $a[1]. If I'm right, then you can actually use this as you intend, but by doing this: $a = array( 2 => "argh", 1 => "blah {$a[2]}", 0 => "test {$a[1]}" ); This is what I would guess is happening:
1. PHP creates $a.
2. The initializer creates $a[0]. When it does this, $a[1] has no value since it has not yet been assigned, so “test {$a[1]}” evalulates to just “test “.
3. Same with $a[1].

If I’m right, then you can actually use this as you intend, but by doing this:
$a = array(
2 => “argh”,
1 => “blah {$a[2]}”,
0 => “test {$a[1]}”
);

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